The sequence of reactions is: $Phenol$ $\xrightarrow[\Delta]{Zn \, dust} X$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} Y$ $\xrightarrow[\Delta]{KMnO_4} Z$. The final product $Z$ is:

Consider the following reactions:
$C_6H_5N_2Cl$ $\xrightarrow{H_2O, 283 \ K} X$ $\xrightarrow{Conc. \ HNO_3} Y$
$X \xrightarrow{Br_2/H_2O} Z$
$Y$ and $Z$ respectively are:

Phenol on distillation with zinc dust gives

Phenol $\xrightarrow[(ii) CO_2 / 140^{\circ}C]{(i) NaOH} A$ $\xrightarrow{H^{+} / H_2O} B$ $\xrightarrow[CH_3COOH, \Delta]{Al_2O_3} C$
In this reaction,the end product $C$ is :

Given below are two statements: One is labelled as $Assertion$ $A$ and the other is labelled as $Reason$ $R$:
Assertion $A$: $pK_a$ value of phenol is $10.0$ while that of ethanol is $15.9$.
Reason $R$: Ethanol is a stronger acid than phenol.
In the light of the above statements,choose the correct answer from the options given below:

What will be the product of the reaction with $HBr$?